Szczegóły publikacji
Opis bibliograficzny
Argument of separation at upgrading in the JIG — Argument rozdziału przy wzbogacaniu w osadzarce / Marian BROŻEK, Agnieszka SUROWIAK // Archives of Mining Sciences = Archiwum Górnictwa ; ISSN 0860-7001 . — 2010 — vol. 55 iss. 1, s. 21–40. — Bibliogr. s. 39–40
Autorzy (2)
Słowa kluczowe
Dane bibliometryczne
| ID BaDAP | 51579 |
|---|---|
| Data dodania do BaDAP | 2010-05-05 |
| Rok publikacji | 2010 |
| Typ publikacji | artykuł w czasopiśmie |
| Otwarty dostęp |  |
| Czasopismo/seria | Archives of Mining Sciences = Archiwum Górnictwa |
Abstract
The necessary condition of distribution of heterogeneous feed to be separated in the pulsating water stream is constituted by the sufficient loosening of particles. Due to the variety of material, both from the point of view of its physical and geometrical properties, the stratification of particles will occur according to settling velocity of particles. The paper presents various approaches to the problem of motion in the liquid medium by a model particle, i.e. a sphere, and an irregular particle, considering the shape and drag coefficients. Interesting and at the same time different is the way of theoretical calculation of the drag coefficient for a sphere according to Finkey for the liquid disregarding viscosity, and according to Abraham, considering the boundary layer which is conditioned by the existence of liquid internal friction forces. After a thorough analysis of the methods, presented by different authors and considering the calculation of the drag coefficient for a spherical particle, taking into account the empirical dependences of the drag coefficient upon Reynolds number, the value ψk = 0,46 was assumed for the drag coefficient, calculated from the formula given by Abraham and consistent with experiment. In the paper the final formula was derived which describes the terminal settling velocity of an irregular particle and which includes the particle projection diameter, reduced density and particle shape coefficients: v = 5,33√x√dp√(k1/k 2).
